You're correct. The Odds ratio is 1.36:
|
|
Cases |
Controls |
|
Risk allele |
a |
b |
|
Other alleles |
c |
d |
Odds ratio = ad/bc
|
G->A exon 4 substitution |
AD patients |
Controls |
|
AG or AA |
7 |
8 |
|
GG |
31 |
48 |
Odds ratio = (7 x 48) / (31 x 8) = 1.32
95% Confidence Interval = .45 – 4.11
In this instance the confidence interval includes 1. Therefore, the allele is not a significant risk factor for AD.
PARK2 looked promising, but there might be a better candidate gene.
Click here to research more and try another one.