You're correct. The Odds ratio is 3.09:
|
|
Cases |
Controls |
|
Risk allele |
a |
b |
|
Other alleles |
c |
d |
Odds ratio = ad/bc
|
SOD2 C47T exon 2 Poly. |
AD patients |
Controls |
|
TT or TC |
21 |
16 |
|
CC |
17 |
40 |
Odds ratio = (21 x 40) / (17 x 16) = 3.09
95% Confidence Interval = 1.30 –7.32
In this instance the confidence interval is above 1. Therefore, the T allele is a significant risk factor for AD.
Good job! You have discovered a gene on chromosome 6 that seems to be linked to Alzheimer disease.
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